Exercise 2

The force can be derived from the potential: \[F=- \frac{\partial V}{\partial q} = - \frac{\partial}{\partial q} H(q, p)\]

From Exercise 1, Lecture 10 it follows: \[ \frac{\partial}{\partial q} H = \{H, p\}\]

Hence \[F = - \{H, p\} = \{p, H\} = \dot{p} = m\ddot{q}\]