Exercise 3
This task is very easy. We differentiate the equation \[ z(t) = z_0 + v_z(0) t + \frac{F_z}{2m}t^2 \]
and we get: \[ \dot{z}(t) = v_z(0) + \frac{F_z}{m}t \]
This task is very easy. We differentiate the equation \[ z(t) = z_0 + v_z(0) t + \frac{F_z}{2m}t^2 \]
and we get: \[ \dot{z}(t) = v_z(0) + \frac{F_z}{m}t \]